Java input validation: ways to implement it by using scanner
![SOLVED: “`java import java.util.Scanner; public class BreakAndContinue public static void main(String[] args) Scanner scnr = new Scanner(System.in); int stop; int result; int n; // Input stop = scnr.nextInt(); result = 0; //](https://cdn.numerade.com/ask_images/42858b9135784d0abcc7d59f44c45b0a.jpg "SOLVED: “`java import java.util.Scanner; public class BreakAndContinue public static void main(String[] args) Scanner scnr = new Scanner(System.in); int stop; int result; int n; // Input stop = scnr.nextInt(); result = 0; //")
SOLVED: “`java import java.util.Scanner; public class BreakAndContinue public static void main(String[] args) Scanner scnr = new Scanner(System.in); int stop; int result; int n; // Input stop = scnr.nextInt(); result = 0; //
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![SOLVED: Given the following Java program: import java.util.Scanner; public class testMyAd public static void main(String[] args) int n; Scanner input = new Scanner(System.in); System.out.print("Enter an integer 1, 2, or 3: "); n=](https://cdn.numerade.com/ask_images/f3a8693fed1141ac90bcd2cdbf658031.jpg "SOLVED: Given the following Java program: import java.util.Scanner; public class testMyAd public static void main(String[] args) int n; Scanner input = new Scanner(System.in); System.out.print(\"Enter an integer 1, 2, or 3: \"); n=")